THIS IS DUE on FRIDAY 12/3/10Explain how these three situations would change a chip board (regardless of the starting value of the chips on the chip board). EX: "The first situation would cause the chip board to change by..... This would happen becuase....."
a. Adding 7 red chips and 13 black chips
b. Adding 15 red chips and 15 black chips
c. Adding 24 red chips and 17 black chips
In Situation “a”, the chip board would change by 7 red chips and 13 black chips and the change would be positive 5. The answer would be positive 5 because the 7 red chips would be canceled out through zero pairs in the 13 black chips. In situation “B” there would be no change on the chip board because the value on the chip board would still be zero. The value on the board would be zero because the chips are exactly the same number in positives and negatives and that causes a zero pair. In situation “c”, the change would be a negative change. The reason it would be a negative change is because there are 24 negative chips and only 17 positive chips. Through zero pairs, there would be a value of negative 7.
ReplyDeleteA. The first situation would cause the chip board to change by 6 this would happen because the red is negative and the black is the positive so -7+13=6
ReplyDeleteB. The second situation would cause the chip board to change by 0 because the red is negative and the black is the positive so -15+15=0
C. The third situation would cause the chip board to change by -7 because the red is negative and the black is the positive so -24+17=-7
Situation “a” the board would change by adding 7 red chips and 13 black chips. The answer would be positive 6 because when you put zero pairs, all the red chips are zero pairs with black chips. Situation “b” the board would change by adding 15 red and 15 black chips. The answer would be 0 because negative 15 and positive 15 are opposites, so the equal each other out. Situation “c” the board would change by adding 24 red and 17 black chips. The answer is negative 7 because when you put zero pairs together, the 17 black would be canceled out.
ReplyDeleteThe first chip board would change by 6. This would happen because when you make zero pairs out of the chips that you added all of the new red chips would go away which adds 6 black chips to the already existing board.
ReplyDeleteThe second chip board not change by any because all of the chips that were added would create fifteen zero pairs and the zero pairs would cancel each other out therefore not adding anything to the original chip board.
The third chip board would change by -7. This would happen because when you make zero pairs out of the new black chips would be canceled out by the red chips leaving 7 red chips. So the already existing board would change by -7.
The first sitution would change the chip board by adding 6 positive chips. This would happen because 13-7=6.
ReplyDeleteThe second situation would not add any chips or take any away because -15 and positive 15 is 0, these are opposites.
The third situation would take away 7 chips from the chip board because 24-17=7.
Adding 7 red chips and 13 black chips to a chip board would cause it to change by positive 6. This would happen because there would be 7 zero pairs and 6 black chips left. If you add 15 red chip and 15 black chips it would not change the chip board because they would all be zero pairs so there would be no more chips left to add. adding 24 red chips and 17 black chips would change the chip board by -7. This would happen because it would have 17 zero pairs and 7 red chips left over and red is negative so its -7.
ReplyDeleteJohn Mark Weikel
ReplyDelete12/1/10
13 positive plus 7 negative will equal positive 5.
15 positive plus 15 negative will equal a zero pare. Or just zero.
17 positive plus 24 negative will equal negative 5.
The process that I used to get these solutions is “keep change change”.
situation would chang becase you first start to do -7+13 would=6 then on the second situation would do -15+15 would=0 then the third situation would be -24+17 would= -7 so it changes every situation
ReplyDeleteThe first situation would cause the chipboard to change by 6, this would happen because when we do 7-(-13) we are pretty much just subtracting 7 from 13 since the positive number is greater which would equal a positive 6 making the chipboard to change by 6.
ReplyDeleteThe second situation would cause the chipboard to change by 0, this would happen because since we have the same positive and negative number 15 they are opposites and opposites always equal to zero. 15-15=0
The third situation would cause the chipboard to change by 7, this would happen because when we do 24-(-17) we are pretty much just subtracting 17 from 24 since the positive number is greater which will equal to a positive 7 making to chipboard to change by 7.
1. the 7 red chips would cancle out 7 of the black chips wich would leve 6 black chips.
ReplyDelete2. the 15 red chips would cancle out 15 of the black chips wich would leve 0 of the chps because they zeroed each other out.
3. the 17 black chips would zero out 17 of the 24 red chips wich would leve 7 red chips.
A.In situation “A” the chip boards amount would change by positive 6. I know this because positive 13 and negative 7 makes 7 zero pairs, leaving 6 black chips left on the chip board.
ReplyDeleteB.In situation “B” the chip board amount would change by 0, because negative 15 and positive 15 are opposites.
C.In situation “C” the chip board amount would change by negative 7 chips.
I know this would happen because negative 24 and positive 17 make 17 zero pairs, leaving 7 red chips left on the chip board.
In the case of situation "A", the amount on the board will change by 6 chips. This happens because since red is negative and black is positive, there will be 7 zero pairs leaving only 6 black chips remaining on the board.
ReplyDeleteFor situation "B", the amount or value left on the board will be zero. This happens becuase the amount of black positive chips and red negative chips are the same, which will all equal out as zero pairs.
In the last situation, "B", the value left on the board is 7 red chips. Because of the fact that there are 24 red chips and 17 black chips and there are 17 zero pairs, only 7 red chips are left on the board, which gives us the answer.
by the way Mrs. Ryon, this is Mio Yamada.
ReplyDelete“A” on a chipboard 13 black plus 7 red would change positive 6 because in 13 black plus 7 red you would start out by making zero pairs and there would be a total of 7 zero pairs because there are only 7 red and 13 black and 13 minus 7 is 6
ReplyDelete“B” On a chip board 15 red plus 15 black would change zero because they have the same absolute value and both of them have 15 chips and if you would make zero pairs there would be 15 zero pairs and so you would take away 15 from both the red and the black chips and that is the exact number that the red and black chips had in absolute value
“C” on a chipboard 24 red plus 17 black would have a change of negative 7 because first you would make zero pairs and since 24 has the largest absolute value it would have 17 taken away because that is the absolute value of 17 black is 17 and 24 sub 17 equals 7 then you would change the sign to the sign with the greatest absolute value
Well in this situation they are adding chips to each side of the board. That really affect the problem. First of all it well change the awnser. lets say you have a chip board with 5 red and 7 black, and then you did one of those changes on them it would affect it. Then the diffrent ones would do it to.
ReplyDeleteThe first situation would cause the chipboard to change by 6 black chips. This is because adding seven more negatives will get rid of 7 out of thirteen black chips and there would be only 6 left to and on to the black positive chips. The second situation would not change anything to the clipboard because the number of chips for the red and black chips are the same and are opposites and will always equal 0.The third situation would change the clip board by 7 red chips because the seventeen black chips would eliminate 17 red chips and leave only 7 red chips to add to the chip board
ReplyDeleteIn situation a,you would get 6. This happens because adding -7 to 0 would be the same as subtracting 7 to 0. Then by adding 13 to -7, you would get 6.
ReplyDeleteIn situation b, you would get 0. This happens because by taking away 15 from 0, you would get -15. And because -15 and 15 have the same absolute value,you would get 0 when you at 15 to -15.
In situation c, you would get 7. This happens because adding -24 would be the same as subtracting 24 from 0, so you would have -24. Then by adding 17 to -27, you would get 7.
The first situation would change by 6, this would happen because adding a negative 7 to a possitive 13 would create/give you a positive 6. It's like subtracting 7 from 13. The second situation would give you a Zero, this would happen because negative 15 and possitive 15 are opposites. Therefore you would get exactly zero. The last situation would change by 6, but it wouldnt be a possitive 6, it would be a negative 6. You can't get a possitive number when you have a greater negative number and subtract a smaller possitive number. No matter what you will end up with a negative. When you subtract negative 24 from possitive 17 you will end up with a negative 6.
ReplyDeleteOn letter a it would change seven red chips and 13 black chips and the answer would be 6, on letter b the answer would be 0 because theres no change there opposites. On letter c it would change by adding 17 black chips and 24 red chips the answer would be -17 because it would have 17 zero pairs and 7 red chips left.w
ReplyDeleteA.) The first situation would cause the chip board to change by positive 6. This would happen because there are 7 red chips and 13 black chips and if we do zero pairs, their would be 7 zero pairs and what would be left is 6 black chips which is positive 6.
ReplyDeleteB.) The second situation would cause the chip board to change by 0. Because there are 15 black chips and 15 red chips and if we do zero pair there would be 15 pairs and what would be left if nothing which would be 0.
C.) The third situation would cause the chip board to change by negative 7. This would happen because there 24 red chips and 17 black chips and if we do zero pairs there would be 17 pairs and there would be 7 red chips left and is negative 7.
A.) The first situation would cause the chip board to change by positive 6. This would happen because there are 7 red chips and 13 black chips and if we do zero pairs, their would be 7 zero pairs and what would be left is 6 black chips which is positive 6.
ReplyDeleteB.) The second situation would cause the chip board to change by 0. Because there are 15 black chips and 15 red chips and if we do zero pair there would be 15 pairs and what would be left if nothing which would be 0.
C.) The third situation would cause the chip board to change by negative 7. This would happen because there 24 red chips and 17 black chips and if we do zero pairs there would be 17 pairs and there would be 7 red chips left and is negative 7.
In situation "A" the chip board would change,because you add 7 red chips and the 13 black chips you would get positive 6. The problem has an addition sign but you dont really add, you subtract, its how you get the answer of positive 6.
ReplyDeleteIn situation "B" the sort of the chip board wouldn't change because when you pair up 5 red chips and 5 black chips together you would get zero pairs.
Situation "C" changes the chip board, because when you add negative 27 and positive 17 you get negative 7.
Well if you had 7 red chip and 13 black chips on a boarded it would change. After you solve it you would have 6 black chips on the board. That’s how much it would be changing, it would be changing by 6. The next one b. is adding 15 red chip and 15 black chips. There both the same number, so your not changing by anything. It would happen because there both the same number and one is negative and the other is positive. Then the last one is adding 24 red chip and 17 black chips. This situation would cause the board to change by 7 chips. This chip is changing by negative 7. This would happen because you have 24 red chips and 17 black chips.
ReplyDeleteThis would happen, because you are changing the value of the original chip board. So because you are doing that the chip board total value would change as well. For situation A you change the chip board by 20 but it is a positive change, because there is more positive than negative. In situation B you would be adding 30 chips to the board, but there is not a change, because it comes out in zero pairs. For situation C you would be change in value of 41, but there be a negative change, because the greater value is negative.
ReplyDelete