THIS IS DUE on FRIDAY 12/3/10Explain how these three situations would change a chip board (regardless of the starting value of the chips on the chip board). EX: "The first situation would cause the chip board to change by..... This would happen becuase....."
a. Adding 7 red chips and 13 black chips
b. Adding 15 red chips and 15 black chips
c. Adding 24 red chips and 17 black chips
Chip board A. would make your answer positive, because adding 7 red chips and 13 black chips make it positive.
ReplyDeleteChip board B. would make the final answer Zero. Because all your doing is adding zero pairs.
Chip board C. would make your answer negative because adding 24 red and 17 black chips makes your answer negative.
Situation 1: The first situation would cause the chip board to change by making the solution of the problem a greater number. This happens because you would be adding more black (positive) chips than red (negative) chips.
ReplyDeleteSituation 2: The second situation would cause the chip board to change because the value would be 0. This happens because both of the chip quantities on the board are the same which means that they are opposites. Opposites will always equal 0 if you add them together.
Situation 3: The third situation would cause the chip board to change by making the solution more of a less value. This happens because you are adding more red (negative) chips than more black (positive) chips.
The first situation would cause the board to change by having the value of positive eleven. This would happen because there are seven red chips and eighteen black chips so it would cause seven zero pairs the there would be eleven black chips left. The second situation would cause the board to have the value of a zero pair because the numbers are opposites. The third situation would cause the board to change by having the value of negative seven. This would happen because there are twenty-four red chips and seventeen black chips so there would be seventeen zero pairs and seven red chips left.
ReplyDeleteThe first situation of adding 7 red chips and 13 black chips would cause the chip board to change by adding 6 black chips (or 6 positive chips) to the original board making a positive change. The second situation of adding 15 red chips and 15 black chips would actually not change the number of black or red chips at all, they are opposites so they cancel each other out making no change to the number that is on the board already. The third situation of adding 24 red chips and 17 black chips would change the number by increasing the number of red chips by 7 (or 7 negative).
ReplyDeleteIn the first situation regardless of how many chips you have at the start you will end up ADDING 8 positive black chips. 7 red chips is equal to -7. 13 black chips is equal to positive 13. Make zero pairs from 7 to 13. So 7 red match up with 7 black. That leaves you with positive 8 black chips to add to your original board.
ReplyDeleteIn the second situation, regardless of how many chips you start with you will add 15 red which equals to -15, and 15 black which equals to positive 15. How many chips you start with will not matter for this. Make zero pairs of 15 red and 15 black. Those 2 numbers are opposites, therefore meaning you will not change the number of chips. It will be like adding 0 to how many chips you have.
In the third situation regardless of how many chips you start with you will add 17 black and 24 red. The first thing you would do is make zero pairs from 17 to 24 since 24 is the bigger number. 17 goes into 24 and that leaves 7 red chips left behind. So it will be adding 7 red chips which equal -7 to the amount you started with.
The first situation would change when you add thirteen black chips and seven red chips by adding or subtracting five. This would happen because the value of thirteen and seven is a positive five. The second situation would change when you add fifteen red chips and fifteen black chips by zero. This would happen because the value of fifteen and fifteen are zero. The third situation would change when you add twenty-four red chips and seventeen black chips by adding or subtracting seven. This would happen because the value of twenty-four and seventeen are seven.
ReplyDeleteThese three situations would change the chip board because there is a black chip which is positive and a red chip which is positive chip. It depends how many black and red chips you put on there. So when you do the math it either comes out positive or negative. Like the first example there are seven red chips and thirteen black chips. So you do the math and it comes out as positive six. Now the second question. There are fifteen red chips and fifteen black chips. So you do the math but these are opposites so they cancel each other out and the answer is zero. Finely the third question. There are twenty four red chips and seventeen black chips. So you do the math and the answer comes out as negative seven. So it all depends on the chips because it is kind of obvious if there is more red chips than black chips it will be negative. If it is the other way around it would be positive.
ReplyDeleteThe first station would cause the clip board to increase by adding 7 red and 13 black chips. The next station would cause adding 15 red and 15 black chips witch = 22 red and 28 black chips. And the next station would cause adding 24 red and 17 black chips witch = 46 red and 41 black chips. The first question would be positive because there are more black chips than red chips, the second question would be positive because there are more black chips than red chips. The last question would be negative because there are more red chips than black chips.
ReplyDeleteThe first situation would cause the chip board to change would be a positive 6 because if you had a chipboard of -7 and +13 you take away 7 from both sides and you will get +6. The second situation would cause the chip board to change would be 0 because -15 and 15 are opposites so it’s like saying 15 – 15 so it would be 0. The third situation would cause the chip board to change would be a negative 7 because -24 take away from + 17 would be -7.
ReplyDeleteA. Adding 7 red chips and 13 black chips would change your board by taking seven zero pairs from the red and black chips. The answer would be positive 6 because there are only positive chips left over.
ReplyDeleteB. Having 15 positive chips and 15 negative chips would change the board by making a zero pair; the answer would be 0 because 15 and -15 are opposites.
C. Adding 24 red chips and 17 black chips would change your chip board by taking away 17 zero pairs, so the answer is -7 because there are only 7 red chips left over.
Chip board A would be positive because if u add 7 red chips and 13 black chips there are 6 black chips left over because the black chips are positive. 7 red chip and the 13 black chips make zero pairs and there are 6 black chips with no pair and that is 6 positive.
ReplyDeleteChip board B would be 0 because 15 red chips and 15 black chips make exactly 15 zero pairs and nothing is left so it is zero.
Chips board C is negative 7 because if u add 24 red chips and 17 black chips they make 17 zero pairs and 7 red chips are left over which is negative 7.
On the first chip board the value would change by 6 because there is 6 more black (positive chips) than red (negative chips). On Chip board b the value would not change because you are adding the same number of each chip or adding opposites. On chip board c the value would change by -7 because there is 7 more red hips than black chips.
ReplyDeleteThe change for answer A. is 6 I got that answer by adding a positive 13 to a negative 7. The change for answer B. is 0 because positive 15 and negtive 15 they cancel each other out. The change for answer C. is -31 because I added -24 to 17, the bigger number is the symbol of the answer.
ReplyDeleteA. 13+-7= 6
B. -15+15= 0
C. -24+17= -31
Situation 1: The board would change because now it would be in a positive value because there are more positive chips then Negative chips. This would happen because there are now 13 black chips and 7 red ones. You would match them up and get a positive answer from it.
ReplyDeleteSituation 2: If you added 15 red chips and 15 black chips then it would be zero. Because there is an even amount to zero each other out making a final answer of 0.
Situation 3: If you added 24 red chips and 15 black chips it would be negative answer because there are more negatives then positive chips
The chip board would change because when you are adding a negative and positive you are getting more zero pairs but it shouldn’t change the result of the amount left over
ReplyDeleteAdding 7 red chips and 13 black chips:
ReplyDeleteRed chips are negative so if you added 7 red chips the value of negatives would go up by 7. Black chips are positive so adding 13 black chips makes 13 more positives on the chip board. When there is a higher value of positive chips then the final value will be positive. Like in this situation, there are 13 black chips and 7 red chips, there for the final value WILL be positive on this chip board.
Adding 15 red chips and 15 black chips:
When adding the same about of chips to both negative chips and positive chips, the value of both chips will be equal. Negative 15 and positive 15 are opposites which make a zero pair. They will cancel each other out to make the final value zero.
Adding 24 red chips and 17 black chips:
Red chips are always negative and black chips are always positive. Adding 17 black chips will give you 17 positives on the chip board. Adding 24 red chips with give you 24 negatives on the chip board. In this situation, there are more red chips so the final value will be negative.
Board A.
ReplyDeleteWould change because if you are adding 7 red chips (negative) to 13 black chips (positive), then the number is going to end up positive.
Board B.
The value would be zero because the numbers cancel each other out, because they are zero pairs.
Board C.
This one would change because if you are adding 24 reds (negative) and 17 black (positive), then the final answer will end up negative.
Bored A: If you add 7 red chips then 13 blacks chips it would be positive because you have to take out the zero pairs, and what would be left 6 positive.
ReplyDeleteBored B: if you add 15 red then 15 black there it would just be zero because they are the same numbers but opposite so it would just be zero.
Bored C: if you add 24 red chips then 17 black chips it would be negative because there would be red chips left over which would be -13.
A if you add 7 red chips and 13 black chips it will change it because there will be 6 more black chips if the starting vale is 0.
ReplyDeleteB for b if you give both side the same amount of red and black chips they will cancel each other out and make zero.
C if you add 24 chips and 17 it will just be the same as a but instead of black having more chips it will be red that has more chips.
A. The first situation would cause the chip board to change by 6. This would happen because if you have negative 7 and 13 positive. The proceger will be -7+13=6.
ReplyDeleteB. The second situation would cause the chip board to change by 0. This would happen because -15 and 15 are zero pars. The proceger will be -15+15=0.
C. The second situation would cause the chip board to change by -31. This would happen because -24 and 17 will added together will be -31. The proceger will be-24+17=31. :) :)
A. The first situation would cause the chip board to change to positive, this would happen because there are more positive chips than negative chips.
ReplyDeleteB. The second situation would cause the chip board not to change, this would happen because they are opposites, and cancel each other out.
C. The third situation would cause the chip board to change to negative, this would happen because there are more negative chips than positive chips.
A.The first situation would cause the chip board to change by making the solution of the problem a positive number. This happens because you would be adding more black chips (positive) than red chips (negative).
ReplyDelete7 red + 13 black = 6 black.
B.The second situation would cause the chip board to have the value of a zero pair. This is because 15 red and 15 black are zero pairs or opposites. They cancel each other out to end up with a value of 0. Opposites or zero pairs will always equal 0 if you add the two opposite together.
C.The third situation would cause the chip board to change by making the solution of the problem a negative number. This happens because you are adding more red chips (negative) than more black chips (positive).
24 red + 17 black = 7 red.
Situation A: Would make the final answer positive, because adding seven red (negative) chips and thirteen yellow (positive) chips make it positive.
ReplyDeleteSituation B: Would make the final answer Zero, because everything that you are doing is adding the zero pairs.
Situation C: Would make your answer negative because adding twenty- four red (negative) chips and seventeen black (positive) chips makes your answer negative.
Chip borad A's answere would be positive 6 because adding thirteen black chips to seven red would make it positive. Chip board B's question would be zero because the two numbers cancel each other out because they are zero pairs. The answer for letter C would be be negative 7.
ReplyDelete1. For the first one it would change it because when you have different amounts the one with the larger amount that determines whether it is positive or negative in this case it would be a positive 6 because the larger amount from the positive cancels out the negative leaving you with the remainder which is positive 6
ReplyDelete2. This one is easy because they are opposites and they are going to cancle each other out so you would have a zero pair
3. In this one you will have a negative answer because your larger number is negative so again you will have zero pairs and that will leave you with rest which would be -7
The first situation would be a positive six since the positive numbers are the greater value, you know its going to be positive and that you know 13-7 gets you 6.
ReplyDeleteThe second situation changes to 0 since opposites cancel each other out.
The third situation equals -8 since the higher number is negative.
A.)When you add 7 red chips and 13 black chips and match them up to make 0 pairs you will get 5 positives.Because I matched up the positive and the negatives to make the 0 pairs. And I ended up with 5 positives.
ReplyDeleteB.) When you add 15 red and 15 black chips and you do 0 pairs you will end up with 0 because you will use all of them.
C.) when you add 24 red chips and 17 black chips and make 0 pairs you will end up with negative 7.
A) Is true because -50 times -800 is positive 40,000. So then -50 times -1000 =50,000 then -50 times 200 = 10,000. Next do 50,000 + -10,000 which that equals 40,000.
ReplyDeleteB) Is not true because -50 times -800 is positive 40,000. Then -50 times 400 = 20,000, and -50 + 32 = -18. So you multiply 20,000 times -18 = -300,000, and so both side are not equal.
C) It is not true because -8 + 4 = -3. Then 12 divide by -8 = 1.5, and so 12 divide by 4 = 3. So u add -1.5 + 3 equal 1.50, and so the both side are not equal.